1 files changed, 55 insertions, 0 deletions
diff --git a/Content/posts/2024-03-26-Derivation-of-the-Quadratic-Equation.md b/Content/posts/2024-03-26-Derivation-of-the-Quadratic-Equation.md
new file mode 100644
index 0000000..0435a6c
--- /dev/null
+++ b/Content/posts/2024-03-26-Derivation-of-the-Quadratic-Equation.md
@@ -0,0 +1,55 @@
+---
+date: 2024-03-26 15:36
+description: Quick derivation of the quadratic equation by completing the square 
+tags: mathematics 
+---
+
+# Quadratic Formula Derivation
+
+The standard form of a quadratic equation is:
+
+$$
+ax^2 + bx + c = 0
+$$
+
+Here, $a, b, c \in \mathbb{R}$, and $a \neq 0$
+
+We begin by first dividing both sides by the coefficient $a$
+
+$$
+\implies x^2 + \frac{b}{a}x + \frac{c}{a} = 0
+$$
+
+We can rearrange the equation:
+
+$$
+x^2 + \frac{b}{a}x = - \frac{c}{a}
+$$
+
+We can then use the method of completing the square. ([Maths is Fun](https://www.mathsisfun.com/algebra/completing-square.html) has a really good explanation for this technique)
+
+$$
+x^2 + \frac{b}{a}x + (\frac{b}{2a})^2 = \frac{-c}{a} + (\frac{b}{2a})^2
+$$
+
+On our LHS, we can clearly recognize that it is the expanded form of $(x + d)^2$ i.e $x^2 + 2x\cdot d + d^2$
+
+$$
+\implies (x + \frac{b}{2a})^2 = \frac{-c}{a} + \frac{b^2}{4a^2} = \frac{-4ac + b^2}{4a^2}
+$$
+
+Taking the square root of both sides
+
+$$
+\begin{align*}
+x + \frac{b}{2a} &= \frac{\sqrt{-4ac + b^2}}{2a} \\
+x &= \frac{\pm \sqrt{-4ac + b^2} - b}{2a} \\
+&= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
+\end{align*}
+$$
+
+This gives you the world famous quadratic formula:
+
+$$
+x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
+$$